Fixed some notation
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		@@ -139,7 +139,7 @@ A,i \in \{1,\dots,n\}\} $$
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**Definition 1.3**
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: $A$ and $B$ are sets. If every element of $A$ is also an element of
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$B$, then $A$ is a *subset* of $B$ and we write $A \subseteq B$. If
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this is not the case, we write $A \subsetneq B$, which means there is
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this is not the case, we write $A \not\subseteq B$, which means there is
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at least one element of $A$ that is not in $B$.
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**Fact 1.2**
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@@ -161,7 +161,7 @@ $2^n$ total leaves of the tree.
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1. Subsets of \{1,2,3,4\}: $\emptyset, \{1\}, \{2\}, \{3\}, \{4\},
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   \{1,2\}, \{1,3\}, \{1,4\}, \{2,3\}, \{2,4\}, \{3,4\}, \{1,2,3\},
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   \{1,2,4\}, \{1,3,4\}, \{2,3,4\}, \{1,2,3,4\}
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   \{1,2,4\}, \{1,3,4\}, \{2,3,4\}, \{1,2,3,4\}$
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* * * *
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@@ -200,9 +200,9 @@ as the set of points in a circle $C$, the universe would be
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$\Bbb{R}^2$.
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**Definition 1.6**
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: $A$ is a set in the universe $U$. The *complement* of $A$ or $A\bar$
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is the set $A\bar = U - A$.
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: $A$ is a set in the universe $U$. The *complement* of $A$ or $\bar A$
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is the set $\bar A = U - A$.
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E.g. if $P$ is the set of prime numbers, then $$
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P\bar = \Bbb{N} - P = \{1,4,6,8,9,10,12,\dots\}
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$$ so $P\bar$ is the set of composite numbers and 1.
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\bar P = \Bbb{N} - P = \{1,4,6,8,9,10,12,\dots\}
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$$ so $\bar P$ is the set of composite numbers and 1.
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