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@ -12,6 +12,8 @@ title: Mathematical Proof Study Notes
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## *Hammack*, 25 Jan 2014
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### Ch 1, Sets
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All of Mathematics can be described with *sets*.
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*set*
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@ -260,3 +262,137 @@ for at least one set $A_{\alpha}$ with } \alpha \in I \}\\
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\bigcap_{\alpha \in I} A_{\alpha} &= \{ x : x \in A_{\alpha} \text {
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for every set $A_{\alpha}$ with } \alpha \in I \}\\
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\end{align}$$
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* * * *
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**Assumptions about Sets that are Number Systems**
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In this text, the familiar commutative, associative, and distributive
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properties of arithmetic operations on numbers are taken for granted
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as axioms that we may use in proofs.
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We also accept as fact the natural ordering of elements in $\Bbb{N}$,
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$\Bbb{Z}$, $\Bbb{Q}$, and $\Bbb{R}$. This includes the *well-ordering
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principle*, i.e. that any non-empty subset of $\Bbb{N} has a smallest
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element.
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**Fact 1.5 (The Division Algorithm)**
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: Given integers $a$ and $b$ with $b > 0$, there exist integers $q$
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and $r$ for which $a = qb + r$ and $0 /leq r < b$. This follows easily
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from the *well-ordering principle*.
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**Russel's Paradox**
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Consider the set defined to be all sets that do not contain
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themselves as elements.
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$$
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A = \{X : X \text{ is a set and } X \notin X \}
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$$
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Now consider the set $X = \{\{\{\{\dots\}\}\}\}$, or $X = \{X\}. It is
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the single-element set of the single-element set, etc. nesting
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infinitely. Its only element is $X$ itself, so $X \in X$. Since $X$
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does not satisfy the prerequisite for inclusion in $A$, which is $X
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\notin X$, then $X \notin A$.
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But is $A$ an element of $A$?
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For a set $X$, the definition of $A$ says that $X \in A$ means the
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same thing as $X \notin X$. So, if we substitute $A$ for $X$, then the
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definition of $A$ must says that $A \in A$ means the same thing as $A
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\notin A$.
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If $A \in A$ is true, then it is false; if $A \in A$ is false, then it
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is true. Paradox!
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Mathematicians eventually settled on a set of axioms called the
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*Zermelo-Fraenkel axioms*. It includes the *well-ordering principle*
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and also an axiom that states that a non-empty set $X$ is not allowed
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to have the property $X \cap x \neq \emptyset$ for all its elements
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$x$ that are sets. This prevents defining $X = \{X\}$.
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### Ch 2, Logic
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Logic is a systematic way of thinking that allows us to deduce new
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information from old information and to parse the meaning of
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sentences.
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Following logic allows one to deduce information correctly, but does
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not imply that all correct deductions produce correct information.
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Correct deduction from incorrect facts will lead to new facts that are
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likely to be incorrect.
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In proving theorems, we apply logic to information considered
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obviously true or to information already proved to be true; then
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anything we deduce with correct logic will also be true (at least so
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far as our assumptions were correct).
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**Statements**
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A statement is a sentence or mathematical expression that is either
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definitely true or definitely false.
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We often use capital letters ($P, Q, R, S$) to stand for specific
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statements.
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We may use variables in statements. We use the form $P(x)$ to describe
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a statement $P$ that involves variable $x$.
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A statement whose truth depends on the value of one or more variables
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is an *open sentence*.
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**And, Or, Not**
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We can combine two logical statements together into a new statement.
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One way is with *and*, denoted $\land$. If both statements combined
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with *and* are true, the resulting statement is also true. If either
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is false, the resulting statement is false.
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Another way is with *or*, denoted $\lor$. If either statement is true,
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the resulting statement is true. If both are false, then the resulting
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statement is also false.
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Any statement can have its truth value inverted by applying *not* to
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it. If we have a true statement $P$, $~P$ is false. If we have a
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false statement $Q$, $~Q$ is true.
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**Conditional Statements**
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Given two statements $P$ and $Q$, we can make a new statement, *if*
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$P$, *then* $Q$. We write such a *conditional statement* as $P \implies
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Q$. In terms of logic, $P \implies Q$ is true *unless* $P$ is true but
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$Q$ is not.
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Note that if $R: P \implies Q$ and $P$ is false, then $R$ is true.
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Alternate phrasings of $P \implies Q$:
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- If $P$, then $Q$
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- $Q$ if $P$
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- $Q$ whenever $P$
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- $Q$, provided that $P$
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- Whenever $P$, then also $Q$
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- $P$ is a sufficient condition for $Q$
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- For $Q$, it is sufficient that $P$
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- $Q$ is a necessary condition for $P$
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- For $P$, it is necessary that $Q$
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- $P$ only if $Q$
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**Biconditional Statements**
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$R: P \implies Q$ is not the same as $S: Q \implies P$. We call $S$ the
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*converse* of $R$.
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When a statement is conditional upon a condition $P$ and its converse
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$Q$, we use the phrase $P$ *if and only if* $Q$. We write it $P \iff
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Q$.
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Alternate phrasings of $P \iff Q$
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- $P$ if and only if $Q$
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- $P$ is a necessary and sufficient condition for $Q$
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- For $P$ it is necessary and sufficient that $Q$
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- If $P$, then $Q$, and conversely.
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