399 lines
12 KiB
Plaintext
399 lines
12 KiB
Plaintext
---
|
|
format: markdown
|
|
toc: yes
|
|
title: Mathematical Proof Study Notes
|
|
...
|
|
|
|
# Texts
|
|
|
|
- *Book of Proof*, Richard Hammack
|
|
|
|
# Reading Notes
|
|
|
|
## *Hammack*, 25 Jan 2014
|
|
|
|
### Ch 1, Sets
|
|
|
|
All of Mathematics can be described with *sets*.
|
|
|
|
*set*
|
|
: A collection of things. The things in the set are called *elements*.
|
|
|
|
An example of a set: $\{2,4,6,8\}$
|
|
|
|
The set of all integers:
|
|
$$ \{\dots, -4, -3, -2, -1, 0, 1, 2, 3, 4, \dots\} $$
|
|
|
|
The dots mean the expressed pattern continues.
|
|
|
|
Sets of infinitely many members are *infinite*, otherwise they are
|
|
*finite*.
|
|
|
|
Sets are *equal* if they have exactly the same elements.
|
|
|
|
E.g. $\{2,4,5,8\} = \{4,2,8,6\}$ but $\{2,4,6,8\} \neq \{2,4,6,7\}$.
|
|
|
|
Uppercase letters often denote sets, e.g. $A = \{1,2,3,4\}$.
|
|
|
|
To express membership, we use $\in$, as in $2 \in A$.
|
|
|
|
To express non-membership, we use $\notin$, as in $5,6 \notin A$.
|
|
|
|
* * * *
|
|
|
|
**Special Sets**
|
|
|
|
$\Bbb{N}$
|
|
: *natural numbers*, the positive whole numbers $\{1,2,3,4,5,\dots\}$
|
|
|
|
$\Bbb{Z}$
|
|
: *integers*, $\{\dots, -4, -3, -2, -1, 0, 1, 2, 3, 4,\dots\}$
|
|
|
|
$\Bbb{Q}$
|
|
: *rational numbers*, $\Bbb{Q} = \{x : x = \frac mn; m,n \in \Bbb{Z};
|
|
n \neq 0\}$.
|
|
|
|
$\Bbb{R}$
|
|
: *real numbers*, the set of all real numbers on the number line.
|
|
|
|
$\emptyset$
|
|
: *empty set*, the unique set with no members, $\{\}$
|
|
|
|
* * * *
|
|
|
|
For finite sets $X$, $|X|$ represents the *cardinality* or *size* of
|
|
the set, which is the number of elements it has. E.g. $|A| = 4$.
|
|
|
|
*set-builder notation* describes sets that are too big or complex to
|
|
be listed out. E.g. the infinite set of even integers: $$
|
|
E = \{2n : n \in \Bbb{Z}\}
|
|
$$
|
|
This can be read as "E is the set of all things of form $2n$, such
|
|
that $n$ is an element of $\Bbb{Z}$."
|
|
|
|
*intervals*
|
|
: For two numbers $a,b \in \Bbb{R}$ with $a < b$, we can form various
|
|
intervals on the number line by listing them as a bracketed pair. A
|
|
parenthesis indicates that side of the interval is *open*, while a
|
|
square bracket indicates that side of the interval is *closed*. A
|
|
closed interval *includes* the element of the pair on the closed side,
|
|
while an open interval does not. Infinite intervals are denoted by
|
|
including $\inf$ as one member of the pair on the open side.
|
|
|
|
* * * *
|
|
|
|
**Exercises 1.1**
|
|
|
|
1. $\{4x-1 : x \in \Bbb{Z}\}$ is
|
|
$\{\dots, -21, -16, -11, -6, -1, 4, 9, 14, 19,\dots \}$
|
|
|
|
* * * *
|
|
|
|
With two sets $A$ and $B$, one can "multiply" them to form the set $A
|
|
\times B$ which is called the *Cartesian product*.
|
|
|
|
**Definition 1.1**
|
|
: An *ordered pair* is a list $(x,y)$ of two things $x$ and $y$,
|
|
enclosed in parentheses and separated by a comma. They are
|
|
distinguished by order; e.g. $(3,4) \neq (4,3)$.
|
|
|
|
**Definition 1.2**
|
|
: The *Cartesian product* of two sets $A$ and $B$ is another set, $A
|
|
\times B$, defined as $A \times B = \{(a,b):a \in A, b \in B\}$.
|
|
|
|
E.g. $\{0,1\} \times \{2,1\} = \{(0,2),(0,1),(1,2),(1,1)\}$
|
|
|
|
**Fact 1.1**
|
|
: If $A$ and $B$ are finite sets, then $|A \times B| = |A| \cdot |B|$.
|
|
|
|
The set $\Bbb{R} \times \Bbb{R}$ can represent the points on the
|
|
Cartesian plane.
|
|
|
|
The idea extends to a 3-list, or *ordered triple*. In general:
|
|
$$ A_1 \times A_2 \times \dots \times A_n = \{
|
|
(x_1,x_2,\dots,x_n) : x_i \in A_i, i \in \Bbb{N} \}
|
|
$$
|
|
|
|
We can also take *Cartesian powers* of sets. For a set $A$ and
|
|
positive integer $n$, $A^n$ is the Cartesian product of $A$ with
|
|
itself $n$ times: $$
|
|
A^n = A \times A \times \dots \times A = \{(x_1,x_2,\dots,x_n):x_i \in
|
|
A,i \in \{1,\dots,n\}\} $$
|
|
|
|
* * * *
|
|
|
|
**Exercises 1.2**
|
|
|
|
1. $A = \{1,2,3,4\}, B = \{a,c\}$
|
|
a. $A \times B =
|
|
\{(1,a),(2,a),(3,a),(4,a),(1,c),(2,c),(3,c),(4,c)\}$
|
|
b. $B \times A =
|
|
\{(a,1),(c,1),(a,2),(c,2),(a,3),(c,3),(a,4),(c,4)\}$
|
|
d. $B \times B = \{(a,a),(a,c),(c,a),(c,c)\}$
|
|
e. $\emptyset \times B = \emptyset$
|
|
f. $(A \times B) \times B = \{((1,a),a),((2,a),a),
|
|
((3,a),a),((4,a),a),((1,c),a),((2,c),a),((3,c),a),
|
|
((4,c),a),((1,a),a),((2,a),c),((3,a),c),((4,a),c),
|
|
((1,c),c),((2,c),c),((3,c),c),((4,c),c)\}$
|
|
|
|
* * * *
|
|
|
|
**Definition 1.3**
|
|
: $A$ and $B$ are sets. If every element of $A$ is also an element of
|
|
$B$, then $A$ is a *subset* of $B$ and we write $A \subseteq B$. If
|
|
this is not the case, we write $A \not\subseteq B$, which means there is
|
|
at least one element of $A$ that is not in $B$.
|
|
|
|
**Fact 1.2**
|
|
: It follows from **1.3** that for any set $B$, $\emptyset \subseteq
|
|
B$. I.e., the empty set is a subset of every set.
|
|
|
|
**Fact 1.3**
|
|
: If a finite set has $n$ elements, it has $2^n$ subsets.
|
|
|
|
This can be shown by drawing a decision tree starting with the empty
|
|
set, with each fork representing a choice of whether to insert the
|
|
next element of the set in question. Since there are two possibilities
|
|
at each fork and $n$ elements to consider for insertion, that gives
|
|
$2^n$ total leaves of the tree.
|
|
|
|
* * * *
|
|
|
|
**Exercises 1.3**
|
|
|
|
1. Subsets of $\{1,2,3,4\}$: $\emptyset, \{1\}, \{2\}, \{3\}, \{4\},
|
|
\{1,2\}, \{1,3\}, \{1,4\}, \{2,3\}, \{2,4\}, \{3,4\}, \{1,2,3\},
|
|
\{1,2,4\}, \{1,3,4\}, \{2,3,4\}, \{1,2,3,4\}$
|
|
|
|
* * * *
|
|
|
|
**Definition 1.4**
|
|
: $A$ is a set. The *power set* of $A$ is another set,
|
|
$\mathscr{P}(A)$, defined to be the set of all subsets of
|
|
$A$. I.e. $\mathscr{P}(A) = \{X:X\subseteq A\}$.
|
|
|
|
**Fact 1.4**
|
|
: If $A$ is a finite set, $|\mathscr{P}(A)| = 2^{|A|}$.
|
|
|
|
* * * *
|
|
|
|
**Definition 1.5**
|
|
|
|
$A$ and $B$ are sets.
|
|
|
|
- The *union* of $A$ and $B$ is the set $A\cup B = \{x : x \in A
|
|
\text{ or } x \in B\}$
|
|
- The *intersection* of $A$ and $B$ is the set $A\cap B = \{x : x \in
|
|
A \text{ and } x \in B\}$
|
|
- The *difference* of $A$ and $B$ is the set $A - B = \{x : x \in A
|
|
\text{ and } x \notin B\}$
|
|
|
|
The operations $\cup$ and $\cap$ obey the commutative law for sets,
|
|
but $-$ does not.
|
|
|
|
- If an expression involving sets uses only $\cap$ or $\cup$,
|
|
parentheses are optional.
|
|
|
|
- If it uses both $\cap$ and $\cup$, parentheses are required!
|
|
|
|
* * * *
|
|
|
|
We usually discuss sets in some context. Our sets in that context will
|
|
naturally be subsets of some other set, which we call the *universal
|
|
set* or just *universe*. If we don't know specifically which set it
|
|
is, we call it $U$.
|
|
|
|
For example, when discussing the set of prime numbers $P$, the
|
|
*universal set* is $\Bbb{N}$. When we discuss geometric figures such
|
|
as the set of points in a circle $C$, the universe would be
|
|
$\Bbb{R}^2$.
|
|
|
|
**Definition 1.6**
|
|
: $A$ is a set in the universe $U$. The *complement* of $A$ or $\overline A$
|
|
is the set $\overline A = U - A$.
|
|
|
|
E.g. if $P$ is the set of prime numbers, then $$
|
|
\overline P = \Bbb{N} - P = \{1,4,6,8,9,10,12,\dots\}
|
|
$$ so $\overline P$ is the set of composite numbers and 1.
|
|
|
|
**Definition 1.7**
|
|
|
|
$A_1, A_2,\dots, A_n$ are sets. Then
|
|
|
|
$$\begin{align}
|
|
A_1 \cup A_2 \cup A_3 \cup \dots \cup A_n &=
|
|
\left\{x : x \in A_i
|
|
\text{ for at least one set $A_i$, for }
|
|
1 \leq i \leq n\right\}\\
|
|
A_1 \cap A_2 \cap A_3 \cap \dots \cap A_n &=
|
|
\left\{x : x \in A_i
|
|
\text{ for every set $A_i$, for }
|
|
1 \leq i \leq n \right\}\\
|
|
\end{align}$$
|
|
|
|
Given $A_1, A_2, \dots, A_n$ we define
|
|
|
|
$$\begin{align}
|
|
\bigcup_{i=1}^{n} A_i &= A_1 \cup A_2 \cup \dots \cup A_n\\
|
|
\bigcap_{i=1}^{n} A_i &= A_1 \cap A_2 \cap \dots \cap A_n\\
|
|
\end{align}$$
|
|
|
|
For example, take the following infinite list of sets:
|
|
|
|
$$
|
|
A_1 = \{-1,0,1\}, A_2 = \{-2,0,2\}, \dots, A_i = \{-i,0,i\}, \dots
|
|
$$
|
|
|
|
We can see that:
|
|
|
|
$$
|
|
\bigcup_{i=1}^{\inf} A_i = \Bbb{Z} \text{ and }
|
|
\bigcap_{i=1}^{\inf} A_i = \{0\}\\
|
|
$$
|
|
|
|
**Definition 1.8**
|
|
|
|
If we have a set $A_{\alpha}$ for every $\alpha$ in some index set $I$,
|
|
then
|
|
|
|
$$\begin{align}
|
|
\bigcup_{\alpha \in I} A_{\alpha} &= \{ x : x \in A_{\alpha} \text {
|
|
for at least one set $A_{\alpha}$ with } \alpha \in I \}\\
|
|
\bigcap_{\alpha \in I} A_{\alpha} &= \{ x : x \in A_{\alpha} \text {
|
|
for every set $A_{\alpha}$ with } \alpha \in I \}\\
|
|
\end{align}$$
|
|
|
|
* * * *
|
|
|
|
**Assumptions about Sets that are Number Systems**
|
|
|
|
In this text, the familiar commutative, associative, and distributive
|
|
properties of arithmetic operations on numbers are taken for granted
|
|
as axioms that we may use in proofs.
|
|
|
|
We also accept as fact the natural ordering of elements in $\Bbb{N}$,
|
|
$\Bbb{Z}$, $\Bbb{Q}$, and $\Bbb{R}$. This includes the *well-ordering
|
|
principle*, i.e. that any non-empty subset of $\Bbb{N} has a smallest
|
|
element.
|
|
|
|
**Fact 1.5 (The Division Algorithm)**
|
|
: Given integers $a$ and $b$ with $b > 0$, there exist integers $q$
|
|
and $r$ for which $a = qb + r$ and $0 /leq r < b$. This follows easily
|
|
from the *well-ordering principle*.
|
|
|
|
**Russel's Paradox**
|
|
|
|
Consider the set defined to be all sets that do not contain
|
|
themselves as elements.
|
|
|
|
$$
|
|
A = \{X : X \text{ is a set and } X \notin X \}
|
|
$$
|
|
|
|
Now consider the set $X = \{\{\{\{\dots\}\}\}\}$, or $X = \{X\}. It is
|
|
the single-element set of the single-element set, etc. nesting
|
|
infinitely. Its only element is $X$ itself, so $X \in X$. Since $X$
|
|
does not satisfy the prerequisite for inclusion in $A$, which is $X
|
|
\notin X$, then $X \notin A$.
|
|
|
|
But is $A$ an element of $A$?
|
|
|
|
For a set $X$, the definition of $A$ says that $X \in A$ means the
|
|
same thing as $X \notin X$. So, if we substitute $A$ for $X$, then the
|
|
definition of $A$ must says that $A \in A$ means the same thing as $A
|
|
\notin A$.
|
|
|
|
If $A \in A$ is true, then it is false; if $A \in A$ is false, then it
|
|
is true. Paradox!
|
|
|
|
Mathematicians eventually settled on a set of axioms called the
|
|
*Zermelo-Fraenkel axioms*. It includes the *well-ordering principle*
|
|
and also an axiom that states that a non-empty set $X$ is not allowed
|
|
to have the property $X \cap x \neq \emptyset$ for all its elements
|
|
$x$ that are sets. This prevents defining $X = \{X\}$.
|
|
|
|
### Ch 2, Logic
|
|
|
|
Logic is a systematic way of thinking that allows us to deduce new
|
|
information from old information and to parse the meaning of
|
|
sentences.
|
|
|
|
Following logic allows one to deduce information correctly, but does
|
|
not imply that all correct deductions produce correct information.
|
|
|
|
Correct deduction from incorrect facts will lead to new facts that are
|
|
likely to be incorrect.
|
|
|
|
In proving theorems, we apply logic to information considered
|
|
obviously true or to information already proved to be true; then
|
|
anything we deduce with correct logic will also be true (at least so
|
|
far as our assumptions were correct).
|
|
|
|
**Statements**
|
|
|
|
A statement is a sentence or mathematical expression that is either
|
|
definitely true or definitely false.
|
|
|
|
We often use capital letters ($P, Q, R, S$) to stand for specific
|
|
statements.
|
|
|
|
We may use variables in statements. We use the form $P(x)$ to describe
|
|
a statement $P$ that involves variable $x$.
|
|
|
|
A statement whose truth depends on the value of one or more variables
|
|
is an *open sentence*.
|
|
|
|
**And, Or, Not**
|
|
|
|
We can combine two logical statements together into a new statement.
|
|
|
|
One way is with *and*, denoted $\land$. If both statements combined
|
|
with *and* are true, the resulting statement is also true. If either
|
|
is false, the resulting statement is false.
|
|
|
|
Another way is with *or*, denoted $\lor$. If either statement is true,
|
|
the resulting statement is true. If both are false, then the resulting
|
|
statement is also false.
|
|
|
|
Any statement can have its truth value inverted by applying *not* to
|
|
it. If we have a true statement $P$, $\sim P$ is false. If we have a
|
|
false statement $Q$, $\sim Q$ is true.
|
|
|
|
**Conditional Statements**
|
|
|
|
Given two statements $P$ and $Q$, we can make a new statement, *if*
|
|
$P$, *then* $Q$. We write such a *conditional statement* as $P \implies
|
|
Q$. In terms of logic, $P \implies Q$ is true *unless* $P$ is true but
|
|
$Q$ is not.
|
|
|
|
Note that if $R: P \implies Q$ and $P$ is false, then $R$ is true.
|
|
|
|
Alternate phrasings of $P \implies Q$:
|
|
|
|
- If $P$, then $Q$
|
|
- $Q$ if $P$
|
|
- $Q$ whenever $P$
|
|
- $Q$, provided that $P$
|
|
- Whenever $P$, then also $Q$
|
|
- $P$ is a sufficient condition for $Q$
|
|
- For $Q$, it is sufficient that $P$
|
|
- $Q$ is a necessary condition for $P$
|
|
- For $P$, it is necessary that $Q$
|
|
- $P$ only if $Q$
|
|
|
|
**Biconditional Statements**
|
|
|
|
$R: P \implies Q$ is not the same as $S: Q \implies P$. We call $S$ the
|
|
*converse* of $R$.
|
|
|
|
When a statement is conditional upon a condition $P$ and its converse
|
|
$Q$, we use the phrase $P$ *if and only if* $Q$. We write it $P \iff
|
|
Q$.
|
|
|
|
Alternate phrasings of $P \iff Q$
|
|
|
|
- $P$ if and only if $Q$
|
|
- $P$ is a necessary and sufficient condition for $Q$
|
|
- For $P$ it is necessary and sufficient that $Q$
|
|
- If $P$, then $Q$, and conversely.
|