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format: markdown
toc: yes
title: Mathematical Proof Study Notes
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# Texts
- *Book of Proof*, Richard Hammack
# Reading Notes
## *Hammack*, 25 Jan 2014
All of Mathematics can be described with *sets*.
*set*
: A collection of things. The things in the set are called *elements*.
An example of a set: $\{2,4,6,8\}$
The set of all integers:
$$ \{\dots, -4, -3, -2, -1, 0, 1, 2, 3, 4, \dots\} $$
The dots mean the expressed pattern continues.
Sets of infinitely many members are *infinite*, otherwise they are
*finite*.
Sets are *equal* if they have exactly the same elements.
E.g. $\{2,4,5,8\} = \{4,2,8,6\}$ but $\{2,4,6,8\} \neq \{2,4,6,7\}$.
Uppercase letters often denote sets, e.g. $A = \{1,2,3,4\}$.
To express membership, we use $\in$, as in $2 \in A$.
To express non-membership, we use $\notin$, as in $5,6 \notin A$.
* * * *
**Special Sets**
$\Bbb{N}$
: *natural numbers*, the positive whole numbers $\{1,2,3,4,5,\dots\}$
$\Bbb{Z}$
: *integers*, $\{\dots, -4, -3, -2, -1, 0, 1, 2, 3, 4,\dots\}$
$\Bbb{Q}$
: *rational numbers*, $\Bbb{Q} = \{x : x = \frac mn; m,n \in \Bbb{Z};
n \neq 0\}$.
$\Bbb{R}$
: *real numbers*, the set of all real numbers on the number line.
$\emptyset$
: *empty set*, the unique set with no members, $\{\}$
* * * *
For finite sets $X$, $|X|$ represents the *cardinality* or *size* of
the set, which is the number of elements it has. E.g. $|A| = 4$.
*set-builder notation* describes sets that are too big or complex to
be listed out. E.g. the infinite set of even integers: $$
E = \{2n : n \in \Bbb{Z}\}
$$
This can be read as "E is the set of all things of form $2n$, such
that $n$ is an element of $\Bbb{Z}$."
*intervals*
: For two numbers $a,b \in \Bbb{R}$ with $a < b$, we can form various
intervals on the number line by listing them as a bracketed pair. A
parenthesis indicates that side of the interval is *open*, while a
square bracket indicates that side of the interval is *closed*. A
closed interval *includes* the element of the pair on the closed side,
while an open interval does not. Infinite intervals are denoted by
including $\inf$ as one member of the pair on the open side.
* * * *
**Exercises 1.1**
1. $\{4x-1 : x \in \Bbb{Z}\}$ is
$\{\dots, -21, -16, -11, -6, -1, 4, 9, 14, 19,\dots \}$
* * * *
With two sets $A$ and $B$, one can "multiply" them to form the set $A
\times B$ which is called the *Cartesian product*.
**Definition 1.1**
: An *ordered pair* is a list $(x,y)$ of two things $x$ and $y$,
enclosed in parentheses and separated by a comma. They are
distinguished by order; e.g. $(3,4) \neq (4,3)$.
**Definition 1.2**
: The *Cartesian product* of two sets $A$ and $B$ is another set, $A
\times B$, defined as $A \times B = \{(a,b):a \in A, b \in B\}$.
E.g. $\{0,1\} \times \{2,1\} = \{(0,2),(0,1),(1,2),(1,1)\}$
**Fact 1.1**
: If $A$ and $B$ are finite sets, then $|A \times B| = |A| \cdot |B|$.
The set $\Bbb{R} \times \Bbb{R}$ can represent the points on the
Cartesian plane.
The idea extends to a 3-list, or *ordered triple*. In general:
$$ A_1 \times A_2 \times \dots \times A_n = \{
(x_1,x_2,\dots,x_n) : x_i \in A_i, i \in \Bbb{N} \}
$$
We can also take *Cartesian powers* of sets. For a set $A$ and
positive integer $n$, $A^n$ is the Cartesian product of $A$ with
itself $n$ times: $$
A^n = A \times A \times \dots \times A = \{(x_1,x_2,\dots,x_n):x_i \in
A,i \in \{1,\dots,n\}\} $$
* * * *
**Exercises 1.2**
1. $A = \{1,2,3,4\}, B = \{a,c\}$
a. $A \times B =
\{(1,a),(2,a),(3,a),(4,a),(1,c),(2,c),(3,c),(4,c)\}$
b. $B \times A =
\{(a,1),(c,1),(a,2),(c,2),(a,3),(c,3),(a,4),(c,4)\}$
d. $B \times B = \{(a,a),(a,c),(c,a),(c,c)\}$
e. $\emptyset \times B = \emptyset$
f. $(A \times B) \times B = \{((1,a),a),((2,a),a),
((3,a),a),((4,a),a),((1,c),a),((2,c),a),((3,c),a),
((4,c),a),((1,a),a),((2,a),c),((3,a),c),((4,a),c),
((1,c),c),((2,c),c),((3,c),c),((4,c),c)\}$
* * * *
**Definition 1.3**
: $A$ and $B$ are sets. If every element of $A$ is also an element of
$B$, then $A$ is a *subset* of $B$ and we write $A \subseteq B$. If
this is not the case, we write $A \not\subseteq B$, which means there is
at least one element of $A$ that is not in $B$.
**Fact 1.2**
: It follows from **1.3** that for any set $B$, $\emptyset \subseteq
B$. I.e., the empty set is a subset of every set.
**Fact 1.3**
: If a finite set has $n$ elements, it has $2^n$ subsets.
This can be shown by drawing a decision tree starting with the empty
set, with each fork representing a choice of whether to insert the
next element of the set in question. Since there are two possibilities
at each fork and $n$ elements to consider for insertion, that gives
$2^n$ total leaves of the tree.
* * * *
**Exercises 1.3**
1. Subsets of $\{1,2,3,4\}$: $\emptyset, \{1\}, \{2\}, \{3\}, \{4\},
\{1,2\}, \{1,3\}, \{1,4\}, \{2,3\}, \{2,4\}, \{3,4\}, \{1,2,3\},
\{1,2,4\}, \{1,3,4\}, \{2,3,4\}, \{1,2,3,4\}$
* * * *
**Definition 1.4**
: $A$ is a set. The *power set* of $A$ is another set,
$\mathscr{P}(A)$, defined to be the set of all subsets of
$A$. I.e. $\mathscr{P}(A) = \{X:X\subseteq A\}$.
**Fact 1.4**
: If $A$ is a finite set, $|\mathscr{P}(A)| = 2^{|A|}$.
* * * *
**Definition 1.5**
$A$ and $B$ are sets.
- The *union* of $A$ and $B$ is the set $A\cup B = \{x : x \in A
\text{ or } x \in B\}$
- The *intersection* of $A$ and $B$ is the set $A\cap B = \{x : x \in
A \text{ and } x \in B\}$
- The *difference* of $A$ and $B$ is the set $A - B = \{x : x \in A
\text{ and } x \notin B\}$
The operations $\cup$ and $\cap$ obey the commutative law for sets,
but $-$ does not.
- If an expression involving sets uses only $\cap$ or $\cup$,
parentheses are optional.
- If it uses both $\cap$ and $\cup$, parentheses are required!
* * * *
We usually discuss sets in some context. Our sets in that context will
naturally be subsets of some other set, which we call the *universal
set* or just *universe*. If we don't know specifically which set it
is, we call it $U$.
For example, when discussing the set of prime numbers $P$, the
*universal set* is $\Bbb{N}$. When we discuss geometric figures such
as the set of points in a circle $C$, the universe would be
$\Bbb{R}^2$.
**Definition 1.6**
: $A$ is a set in the universe $U$. The *complement* of $A$ or $\overline A$
is the set $\overline A = U - A$.
E.g. if $P$ is the set of prime numbers, then $$
\overline P = \Bbb{N} - P = \{1,4,6,8,9,10,12,\dots\}
$$ so $\overline P$ is the set of composite numbers and 1.
**Definition 1.7**
$A_1, A_2,\dots, A_n$ are sets.
$$\begin{align}
A_1 \cup A_2 \cup A_3 \cup \dots \cup A_n &=
\left\{x : x \in A_i
\text{ for at least one set $A_i$, for }
1 \leq i \leq n\right\}\\
A_1 \cap A_2 \cap A_3 \cap \dots \cap A-n &=
\left\{x : x \in A_i
\text{ for every set $A_i$, for }
1 \leq i \leq n \right\}\\
\end{align}$$